You are given a string num
, representing a large integer. Return the largest-valued odd integer (as a string) that is a non-empty substring of num
, or an empty string ""
if no odd integer exists.
A substring is a contiguous sequence of characters within a string.
Input: num = "52" Output: "5" Explanation: The only non-empty substrings are "5", "2", and "52". "5" is the only odd number.
Input: num = "4206" Output: "" Explanation: There are no odd numbers in "4206".
Input: num = "35427" Output: "35427" Explanation: "35427" is already an odd number.
1 <= num.length <= 105
num
only consists of digits and does not contain any leading zeros.
impl Solution {
pub fn largest_odd_number(num: String) -> String {
let mut num = num.into_bytes();
while *num.last().unwrap_or(&1) % 2 == 0 {
num.pop();
}
String::from_utf8(num).unwrap()
}
}